Question

the largest number which divides 411,752 and 1013 leaving remainder 8 in each case is​

Answer 1

Answer:

I hope it will help you.

Step-by-step explanation:

A no. divide 411752 leaving remainder 8. so that no. must divide 411752-8=411744

A no. divide 1013 leaving remainder 8. so that no. must devide 1013-8=1005

Largest no. that divide 411752 and 1013 leaving remainder 8 is HCF of 411744 and 1005

And HCF is 3

So your Answer is 3

Please reverify answer by finding HCF of 411744 and 1005

Answer 2

the largest number which divides 411,752 and 1013 leaving remainder 8 in each case is​:

Given,

411 - 8 = 403

752 - 8 = 744

1013 - 8 = 1005

The factors of 403 are 1, 13, 31, 403

The factors of 744 are 1, 2, 3, 4, 6, 8, 12, 24, 31, 62, 93, 124, 186, 248, 372, 744

The factors of 1005 are 1, 3, 5, 15, 67, 201, 335, 1005

HCF of 403, 744 and 1005 is 1

Therefore, 1 is the largest number which divides 411,752 and 1013 leaving remainder 8 in each case