Question

the largest number which divides 615 and 963 leaving reminder 6 in each case is?​

Answer 1

Answer:

To find: the largest number which divides 615 and 963 leaving remainder 6 in each case.

Solution:

Let the HCF of 615 and 963 be x.

Since it is given remainder is 6 in each case,  

Therefore for the numbers to be completely divisible, 6 should be subtracted from both the numbers.

Therefore new numbers are:

615-6 = 609

963-6 = 957

Prime factors of 609 = 3 × 3 × 29

Prime factors of 957= 3 × 11 × 29

Therefore HCF of 609 and 957 is: 3 × 29 = 87

Hence the largest number which divides 615 and 963 leaving remainder 6 in each case is 87.

Step-by-step explanation:

Answer 2

Here’s it
Pls mark it as brainliest and thank me