Question

The largest number which divides 62, 132 and 237 to leave the same remainder in each case is

Answer 1

Answer:

35

Step-by-step explanation:

If the same remainder leaves.

Then we subtract

(132-62),(237-132),(237-62)

70,105,175

The HCF of all three is 35

Answer 2

Answer:

35

Step-by-step explanation:

If all the numbers leave the same remainder then,

Subtract as follows:

(132-62), (237-132), (237-62)

70,  105, 175

HCF of all the numbers is 35

So the answer you are looking for is 35.

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