Question

The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively, is

Answer 1

ur answer is 13

Explanation: Since 5 and 8 are the remainders of 70 and 125, respectively. Thus after subtracting these remainders from the numbers, we have the numbers

65 = (70 − 5), 117 = (125 − 8) which is divisible by the required number.

Now required number = H.C.F of (65,117)

117=65×1+52
65=52×1+13
52=13×4+0
H.C.F(65,117)=13

hope it's helps you

Answer 2

${\huge {\ \: {\tt {\color{pink}{13}}}}}$

Step-by-step explanation:

Required largest number,

HCF of (70-5) and (125-8)

65 and 117 , respectively

now, taking prime factorization of 65 and 117

65 = 5 × 13

117 = 3 × 3 × 13

HCF = 13

${\ { {\bf {\color{pink}{so, answer \: is \: 13 }}}}}$