Math, asked by jonotix597, 8 months ago

The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively, is

Answers

Answered by Anonymous
2
ur answer is 13

Explanation: Since 5 and 8 are the remainders of 70 and 125, respectively. Thus after subtracting these remainders from the numbers, we have the numbers

65 = (70 − 5), 117 = (125 − 8) which is divisible by the required number.

Now required number = H.C.F of (65,117)

117=65×1+52
65=52×1+13
52=13×4+0
H.C.F(65,117)=13

hope it's helps you
Answered by ironmanavenger0890
2

Answer:

70-5=65

125-8=117

both are divisible by 13

factors of 65 :-1 5 13 65

factors of 117:-1 3 9 13 39

in both the largest no. is 13

hence answer is 13

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