Question

The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively, is​

Answer 1

ur answer is 13

Explanation: Since 5 and 8 are the remainders of 70 and 125, respectively. Thus after subtracting these remainders from the numbers, we have the numbers

65 = (70 − 5), 117 = (125 − 8) which is divisible by the required number.

Now required number = H.C.F of (65,117)

117=65×1+52

65=52×1+13

52=13×4+0

H.C.F(65,117)=13

hope it's helps you

Answer 2

Answer:

13

(a) Since, 5 and 8 are the remainders of 70 and 125, respectively. Thus, after subtracting these remainders from the numbers, we have the numbers 65 = (70-5), 117 = (125 – 8),

which is divisible by the required number. Hence, 13 is the largest number which divides 70 and 125, leaving remainders 5 amnd 8.