Question

The largest number which divides 719 and 930 leaving remainders 5 and 6, respectively.

Answer 1

719-5=715
930-6=924
715=5*11*13
924=2²*3*11*7
Hcf is 11
11 is the number which divides 719 and 930 leaving the remainders 5,6
Hope it helps!!

Answer 2

42 is the largest integer which divides 719 and 930 leaving remainders 5 and 6 respectively.

Given:

• Number divides 719 and 930 leaving remainders 5 and 6 respectively

To Find:

• Largest Integer

Solution:

Step 1:

Assume that largest integer is k

then   719 = Ak  + 5   => Ak = 714

and  930 = Bk  + 6  => Bk = 924

Hence k is the HCF of 924 and 2310

Step 2:

Find HCF pf 924 and 714

924= 714 x 1  + 210

714 = 210 x 3 + 84

210 = 84 x 2 + 42

84 = 42 x 2

Hence 42 is the HCF

42 is the largest integer which divides 719 and 930 leaving remainders 5 and 6 respectively.