The largest number which when divided by 20, 25, 30 and 36 leaves a remainder 4 in each case.
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Hi Mate !!
The no. which is divisible by 20 , 25 , 30 and 36 leaving remainder 4 in each case will be their ( LCM + 4 )
LCM of 20 , 25 , 30 and 36 by prime factorization method :-
20 :- 2 × 2 × 5
25 :- 5 × 5
30 :- 2 × 3 × 5
36 :- 2 × 2 × 3 × 3
LCM ( 20 , 25 , 30 , 36 ) :- 2 × 2 × 3 × 3 × 5 × 5 = 900
Required number :- ( LCM + 4 )
900 + 4 = 904
So, 904 is the no. !!
The no. which is divisible by 20 , 25 , 30 and 36 leaving remainder 4 in each case will be their ( LCM + 4 )
LCM of 20 , 25 , 30 and 36 by prime factorization method :-
20 :- 2 × 2 × 5
25 :- 5 × 5
30 :- 2 × 3 × 5
36 :- 2 × 2 × 3 × 3
LCM ( 20 , 25 , 30 , 36 ) :- 2 × 2 × 3 × 3 × 5 × 5 = 900
Required number :- ( LCM + 4 )
900 + 4 = 904
So, 904 is the no. !!
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