The largest numbers which divides 30, 78 and 102 to leave the same remainder in each case is
(a)24 (b) 20 (c) 8 (d) 16
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answer is your question bro
not sure but .........(a)
not sure but .........(a)
AnilSharmaArt:
So our answer is correct ....mark as brainliest answer
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Hello friends!!
Here is your answer :-
Solving all..
(a) 24
30 ÷ 24
Remainder = 6
78 ÷ 24
Remainder = 6
102 ÷ 24
Remainder = 6
# In each case, remainder is same
(b) 20
30 ÷ 20
Remainder = 10
78 ÷ 20
Remainder = 18
102 ÷ 20
Remainder = 2
# Remainder is not same in any case.
(c) 8
30 ÷ 8
Remainder = 8
78 ÷ 8
Remainder = 6
102 ÷ 8
Remainder = 6
# Remainder is not same in each case.
(d) 16
30 ÷ 16
Remainder = 14
78 ÷ 16
Remainder = 14
102 ÷ 16
Remainder = 6
# Remainder is not same in each case.
Bcoz if divides 30, 78 and 102 by 24, it leaves same remainder.
Hope it helps you.. ^_^
#Be Brainly
Here is your answer :-
Solving all..
(a) 24
30 ÷ 24
Remainder = 6
78 ÷ 24
Remainder = 6
102 ÷ 24
Remainder = 6
# In each case, remainder is same
(b) 20
30 ÷ 20
Remainder = 10
78 ÷ 20
Remainder = 18
102 ÷ 20
Remainder = 2
# Remainder is not same in any case.
(c) 8
30 ÷ 8
Remainder = 8
78 ÷ 8
Remainder = 6
102 ÷ 8
Remainder = 6
# Remainder is not same in each case.
(d) 16
30 ÷ 16
Remainder = 14
78 ÷ 16
Remainder = 14
102 ÷ 16
Remainder = 6
# Remainder is not same in each case.
Bcoz if divides 30, 78 and 102 by 24, it leaves same remainder.
Hope it helps you.. ^_^
#Be Brainly
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