Question

The largest numbers which divides 30, 78 and 102 to leave the same remainder in each case is
(a)24 (b) 20 (c) 8 (d) 16

Answer 1

answer is your question bro

not sure but .........(a)

Answer 2

Hello friends!!

Here is your answer :-

Solving all..

(a) 24

30 ÷ 24

Remainder = 6

78 ÷ 24

Remainder = 6

102 ÷ 24

Remainder = 6

# In each case, remainder is same


(b) 20

30 ÷ 20

Remainder = 10

78 ÷ 20

Remainder = 18

102 ÷ 20

Remainder = 2

# Remainder is not same in any case.


(c) 8

30 ÷ 8

Remainder = 8

78 ÷ 8

Remainder = 6

102 ÷ 8

Remainder = 6

# Remainder is not same in each case.


(d) 16

30 ÷ 16

Remainder = 14

78 ÷ 16

Remainder = 14

102 ÷ 16

Remainder = 6

# Remainder is not same in each case.


$option \: \: (a) \: \: is \: \: correct.$


Bcoz if divides 30, 78 and 102 by 24, it leaves same remainder.

Hope it helps you.. ^_^

#Be Brainly