Question

The largest of three consecutive multiples of 7 whose sum gives 777 ?

Answer 1

Given:- The largest of three consecutive multiples of 7 whose sum gives 777 ?⤵

Solution:-⤵

As given,the three consecutive multiples of 7 will be of the form:

x,x+7 and x+14

Then according to the question,

x+x+7+x+14=777

3x+21=777

3x=756

x=

3

756

=252

Multiples are 252,259,266.

Answer 2

Answer:

7n + 7(n+1) + 7(n+2)= 777

3(n+1) = 111

n+1 = 111/3

n +1 = 37

n = 37 - 1

n = 36

The largest among 7n + 7(n+1) + 7(n+2) is  7(n+2).

so we will solve  7(n+2)

⇒ 7(n+2)

⇒ 7(36 + 2)

⇒ 7× 38

⇒ 266

266 is the largest of three consecutive multiples of 7 whose sum gives 777

Step-by-step explanation:

Hope this helps