Chemistry, asked by 143chaithu, 9 months ago

The largest possible magnitude of the orbital angular momentum for n=4 is?

Answers

Answered by sonuvuce
3

The largest possible magnitude of the orbital angular momentum for n = 4 is \boxed{2\sqrt{3}\frac{h}{2\pi}}

Explanation:

The orbital angular momentum is given by

\boxed{L=\sqrt{l(l+1)}\frac{h}{2\pi}}

For n=4

l=0,1,2,3

The maximum value of l is 3

Therefore, maximum orbital angular momentum

L=\sqrt{3(3+1)}\frac{h}{2\pi}

\implies L=\sqrt{4\times 3}\frac{h}{2\pi}

\implies L=2\sqrt{3}\frac{h}{2\pi}

Hope this answer is helpful.

Know More:

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