Question

The largest possible magnitude of the orbital angular momentum for n=4 is?

Answer 1

The largest possible magnitude of the orbital angular momentum for n = 4 is $\boxed{2\sqrt{3}\frac{h}{2\pi}}$

Explanation:

The orbital angular momentum is given by

$\boxed{L=\sqrt{l(l+1)}\frac{h}{2\pi}}$

For $n=4$

$l=0,1,2,3$

The maximum value of $l$ is 3

Therefore, maximum orbital angular momentum

$L=\sqrt{3(3+1)}\frac{h}{2\pi}$

$\implies L=\sqrt{4\times 3}\frac{h}{2\pi}$

$\implies L=2\sqrt{3}\frac{h}{2\pi}$

Hope this answer is helpful.

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