Math, asked by shahakashkumar56, 7 months ago

The largest two-digit number divisible by 8 is-
a) 96
b) 97
c) 98
d) 99

Answers

Answered by MalayaDhal
0

Answer:

96 is the answer.......

Answered by ruhi08
1

Answer:

The largest two digit number divisible by 8 is 96.

Step-by-step explanation:

Lowest among 3 digits number=100, which is divisible by 4 and quotient is 25. So largest 2 digit number divisible by 4 must have quotient 24, and the number is 24×4=96

For 6, 100/6 , quotient 16, remainder 4. Here the largest 2 digit number = 100–4=96

For ,8, 100/8, quotient 12, remainder again 4, in this case also largest 2 digit number divisible by 8 = 100–4=96

For 12, 100/12, quotient =8 , remainder again 4.Again largest 2 digit number divisible by 12= 100–4=96.

So largest 2 digit number divisible by 4, 6,8,12 is 96

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