Math, asked by sarakshi4214, 5 hours ago

the last digit in the expansion of 41^n-1 where n is positive, is?​

Answers

Answered by pradeeprock5476
0

Answer:

1024

Step-by-step explanation:

If n be a positive integer and P(n):45n−54n <br> When n=3 then the last digit of the expression will be -1024

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