Question

The last digit of 2⁹×5¹³¹ is..?

Answer with proper method pls..​

Answer 1

Answer:

Last digit of 2⁹×5¹³¹  = 0

Step-by-step explanation:

Last digit of 5ⁿ = 5 for any n>0

Last possible digit of 2ⁿ occur in cycle of 2, 4, 8, 6. That is cycle of 4 numbers.

Last digit of 2⁹ = 9 mod 4 = 1

that is 2¹ = 2

So, Last digit of 2⁹×5¹³¹ = last digit of 2⁹ x last digit of 5¹³¹ = 2 x 5 = 10

Hence, Last digit of 2⁹×5¹³¹  = 0