The last digit of the number 8^26 is
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Well, you can solve this using theory of congruence too, but i will prefer the easier method, it’s quite trivial to note that the last digit of powers of 8 get repeated at regular intervals.
notice last digit in each case:-
8^1 = 8
8^2 = 64
8^3 = …2
8^4 = ..6 (when power mod 4 = 0)
8^5 = …8 (when power mod 4 = 1)
8^6 =…4 (when power mod 4 = 2)
8^7 = …2 (when power mod 4 = 3)
8^8 = ….6 (when power mod 4 = 0)
and so on.. so the last digits gets repeated at regular intervals of 4.
divide 2016 by 4, you will get a remainder 0, so last digit will be 6.
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