Question

The last number which when divided by 15,25,35 and 42 remains in each case is

Answer 1

Answer:

The least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case is 1897.

Step-by-step explanation:

To find : The least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case

Step-by-step explanation:

We find the LCM of 15,27,35 and 42.

2 | 15  27  35  42

3 | 15  27  35  21

3  | 3    9    35  7

3  | 1     3    35   7

7  | 1     1    35   7

5  | 1     1    5    1

    | 1     1     1    1

In each case it leaves a remainder 7 so we add 7 in the LCM of the numbers.

i.e. 1890+7 = 1897.

Therefore, The least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case is 1897.

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