Question

The last term of an



a.pis 119 anf the 8rh term from the end is 19 then the common difference of the



a.p is

Answer 1

Answer:

100/7

Explanation:

let the mth term be the last term

last term= a+ (m-1)d

119 = a + (m-1)d

m-1=(119-a)/d

m=(119-a)/d+1........(i)

now,

8 th term from last= a+ (m-8)d

19=a+(m-8)d

m-8=(19-a)/d

m=(19-a)/d+8.......(ii)

from(i) and (ii)

(119-a)/d + 1=(19-a)/d + 8

(119-a)/d-(19-a)/d=8-1

(119-19-a+a)/d=7

100/d=7

d=100/7

Hope it helps....