Question

The last term of an ap is 101 if the 11th term is 28.5 and the sum of it terms is 2090.find the number of terms in the sequence

Answer 1

Answer:

38

Step-by-step explanation:

2090 = 11 * 19 * 10

n/2 * (a+l) = 2090 and a+10d = 28.5

Assuming a+l as 110 and l is given as 101 so a is 9

so n is 2090 * 2 / 110 = 38

a+l cannot be 190 as then decreasing A.P. will form which is not possible as in question it is increasing A.P.