Question

the last term of an AP is 119 and the 8th term from the end is 91 then the common difference of the AP is
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Answer 1

Answer:

As per given , we have

Last term = 119

8th term from the end = 91

Since the AP is starting from the end , let a = 118 and d = common difference for the given arithmetic progression from the end.

Since nth term = a + (n-1)d

119 + (8-1)d = 91

119 + 7d = 91

7d = 91 -119 7d = -28

d = -28/ = -4

Now, the common difference of AP is -d = -(-4) = 4

Hence , the common difference of the AP is 4.

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