the last term of series 0.008 ,0.04 ,0.2 to 11 terms is
Answers
Answered by
0
Answer:
It is given that the first term of G.P is a
1
=0.008 and the second term is a
2
=0.04, therefore,
r=
a
1
a
2
=
0.008
0.04
=5
We know that the formula for the nth term of an G.P is T
n
=ar
n−1
, where a is the first term, r is the common ratio.
It is given that the first term is a=0.008 and the common ratio is r=5, thus,
T
4
=0.008×(5)
4−1
=0.008×5
3
=0.008×125=1
T
8
=0.008×(5)
8−1
=0.008×5
7
=0.008×78125=625
Hence, T
4
=1 and T
8
=625.
Similar questions