Question

The last term of series x^2, x, 1,...to 31 terms is

Answer 1

Answer:

$\frac{1}{ {x}^{28} }$

This will be your answer

Step-by-step explanation:

$a = {x}^{2} \\ r = \frac{1}{x} \\ a31 = a{r}^{31 - 1} \\ = {x}^{2} \times { (\frac{1}{x}) }^{30}$

$\\ = {x}^{2} \times \frac{1}{ {x}^{30} } \\ = \frac{1}{ {x}^{30 - 2} } \\ = \frac{1}{ {x}^{28} }$