Math, asked by Ranjitsinghvirk89041, 9 months ago

The last term of the series x^2 ,x,1 ....To 31 terms is

Answers

Answered by Sairaj010
1

Answer:

x raised to -28 is the required answer

Step-by-step explanation:

use formula

Tn=ar**(n-1)

where Tn is nth term

a is first term

r is common ratio

Answered by ansumansingh2707
4

Answer:

Ans = 1 / x^28 ✔️

Step-by-step explanation:

Each term is given by Tn=arn−1 where a is the first term and r is the common ratio i.e. Tn+1Tn.

In this case we have r=x/x2 = 1/x and a=x2.

So putting n=31 we have

T31=x^2(1/x)^31−1

=x^2−30

=x^−28

or 1/x^28

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