Question

The last term of the series x^2, x, 1, .... to 31 terms is
(a)
(b) 1/x
(c) 1/x28
​

Answer 1

Answer:

1 / x^28

Step-by-step explanation:

Each term is given by Tn=arn−1 where a is the first term and r is the common ratio i.e. Tn+1Tn.

In this case we have r=x/x2 = 1/x and a=x2.

So putting n=31 we have

T31=x^2(1/x)^31−1

=x^2−30

=x^−28

or 1/x^28