Question

the last term of the series x², x ,1,......to 31 term is
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Answer 1

Answer:

In this case we have r=xx2=1x and a=x2. Every term is the previous divided by x. So, the first term is x2, thus the second is x2/x=x, the next is x/x=1, etc. Thus, the 31st term is 1/x28 as described by option