the last three digit numbers are 3 zeros then it is always divisiblem by
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The reason is that every time you go above 10, you increase the value in the tens column by 1, and decrease the value of the units by 10. The net result is that the sum of the digits decreases by 9. So it works with 3, because when you get to 12, the sum of the digits is 12-9 or 3 (which is divisible by 3).
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