Question

The latent heat of fusion of water is 8080 calories/g. Heat capacity of a substance is defined as the heat required to raise the temperature of 11g of that substance by 1^{\circ}1∘. For example, latent heat of ice is 0.50.5 calorie/g degree. This means that to raise the temperature of ice from -4^{\circ}−4∘ to -2^{\circ}−2∘, we have to provide (-2 - (-4)) \times 0.5(−2−(−4))×0.5 calorie of heat = 1=1 calorie. With the above mentioned information, how much calories of heat will be required to convert 88g of ice at -10^{\circ}−10∘ into water at 10^{\circ}10∘? Heat capacity of water is 11 calorie/gram degree. (Volume of water can be taken equal to that of ice) A 400400 calories B 480480 calories C 600600 calories D 640640 calories​

Answer 1

Answer:

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Answer 2

Answer:

The latent heat of fusion of water is 8080 calories/g. Heat capacity of a substance is defined as the heat required to raise the temperature of 11g of that substance by 1^{\circ}1∘. For example, latent heat of ice is 0.50.5 calorie/g degree. This means that to raise the temperature of ice from -4^{\circ}−4∘ to -2^{\circ}−2∘, we have to provide (-2 - (-4)) \times 0.5(−2−(−4))×0.5 calorie of heat = 1=1 calorie. With the above mentioned information, how much calories of heat will be required to convert 88g of ice at -10^{\circ}−10∘ into water at 10^{\circ}10∘? Heat capacity of water is 11 calorie/gram degree. (Volume of water can be taken equal to that of ice) A 400400 calories B 480480 calories C 600600 calories D 640640 calories