the latent heat of vaporization of water is 2240J if work done in process of vaporization of 1g is 168J then increasing internal energy is
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2
Answer:
2072 joules
Explanation:
We know that for first law of thermodynamics, the equation is-
Q=ΔE+ΔW
Here, Q=2240;ΔE=? ΔW=168
ΔE=Q−ΔW
By putting all the values, we get-
ΔE=2240−168=2072J
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