the lateral surface area of a cube is 4 times square of its edge, find the edge of the cube whose lateral surface area is 4x2+8- root128x
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let a be the side of the cube
accordind to question
4(4a^2)=a^2
4(4x^2-root128x +8)=a^2
find the value of x
a=4 ,b=-128 , c=8
x= -b =root (b^2 -4ac)/2a
=root128 +root(128 -4*4*8)/2a
x=root 128+(128 -128)/8
x=root128/8
now putting it in equation
4*root128/2=a^2
128^1/4/root2=a
32/root2=a
a=16root2
a=16root2
accordind to question
4(4a^2)=a^2
4(4x^2-root128x +8)=a^2
find the value of x
a=4 ,b=-128 , c=8
x= -b =root (b^2 -4ac)/2a
=root128 +root(128 -4*4*8)/2a
x=root 128+(128 -128)/8
x=root128/8
now putting it in equation
4*root128/2=a^2
128^1/4/root2=a
32/root2=a
a=16root2
a=16root2
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