Math, asked by prawinkumar, 10 months ago

The lateral surface area of a hollow cylinder is 1188 square cm.It is cut along its height to obtain a rectangle.Find the perimeter of rectangle if the height of the cylinder is 44cm.​

Answers

Answered by jahnavvyas
7

Answer:

hope this may help you

Step-by-step explanation:

Given:

Lateral surface area of hollow cylinder= 4224 cm²

Height of a hollow cylinder (h)= 33 cm

Lateral surface area or curved surface area of hollow cylinder= 2πrh

4224 = 2×(22/7) × r × 33

r=(4224×7) / 2×22×33

r= (64 × 7)/22

Length of rectangular sheet= 2πr

= 2×(22/7)× (64 × 7)/22

=64 × 2

= 128 cm

Perimeter of rectangular sheet = 2(l+b)

= 2(128+33)

= 2 × 161

= 322 cm

Hence, perimeter of rectangular sheet is 322 c

Answered by ykadian2014
2

Answer:

I hope it will help you all

Step-by-step explanation:

Given,

Lateral Surface Area of hollow cylinder= 4224cm²

Height of a hollow cylinder (h) = 33 cm

Lateral surface area or curved surface area of hollow cylinder= 2πrh

4224=2*22/7*r*33

r=(4224*7)/2*22*33

r=(64*7)/22

Length of rectangular sheet =2πr

(2*22/7)*64*7/22

64*2=128cm

Perimeter of rectangular sheet= 2(l+b)

2(128+33)

2*161=322 cm

hence, perimeter of rectangular sheet is 322.

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