Question

the lateral surface area of a hollow cylinder is 4224 cm square. it is cut along its height and formed a rectengular sheet of a width 33 cm. find the perimeter of rectengular sheet.

Answer 1

LSA OF CYLINDER = 4224CM2
WIDTH OF THE RECTANGLE = 33CM
HEIGHT OF THE CYLINDER = LENGTH OF THE RECTANGLE

L×B=4224
L×33=4224
L=4224/33
L=128

PERIMETER OF THE RECTANGLE
=2(L+B)
=2(128+33)
=2(161)
=322

Answer 2

lateral surface area of cylinder =4224cmlength of the rectangle = l              33*l=4224                   l=4224/33=128cm
perimeter of rectangle sheet = 2[l+b]                                              =2[33+128]                                              =2*161                                              =322cm