Question

The lateral surface area of a hollow cylinder is 4224 cm.
It is cut along its height and formed a rectangular sheet
of width 33 cm. Find the perimeter of rectangular sheet?​

Answer 1

Answer:

LSA=4224m^

LSA of a cylinder = Area of a rectangle

Area of a rectangle = l×b

4224 = l×33

therefore l = 4224/33 = 128

Perimeter = 2(l+b)

= 2(128+33)

= 2(161)

= 322cm

Answer 2

Answer:

Step-by-step explanation:

lateral surface area is 4224cm2

width is 33cm ie height is equal to 33cm

so

2πrh=4224cm2

2×22/7×r×33=4224

r=  4224×7÷2×22×33

r=20.36cm

length of rectangle = circumference of the top circle of the cylinder

length= 2πr

2×22/7×20.36= 127.977cm approx 128 cm

so perimeter is = 2 (l+b)

2(128 + 33)= 322cm