The lateral surface area of a hollow cylinder is 4224 cm.It is cut along its height and formed a rectangula
sheet of width 33 cm. Find the perimeter of rectangular sheet?
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Answered by
4
Answer:
L.S.A of cylinder = 4224cm^2
Width= 33cm
width will be the height of cylinder
h=33cm
length of rectangle sheet will be 2/pi r
2/pi rh = l×b
4224=l×33
l=4224÷33
= 128 cm
l=128cm
b=33cm
perimeter of rectangular sheet
=2(l+b)
=2(128+33)
=2×161
=322 cm
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Answered by
1
Given:
Lateral surface area of hollow cylinder=
4224 cm²
Height of a hollow cylinder (h)= 33 cm
Formula used:-
Lateral surface area or curved surface area
of hollow cylinder= 2πrh
solutions:
4224 = 2×(22/7) × r × 33
r=(4224×7) / 2×22×33
r= (64 × 7)/22
Length of rectangular sheet= 2πr
= 2×(22/7)× (64 × 7)/22
=64 × 2
= 128 cm
Now,
Perimeter of rectangular sheet = 2(l+b)
= 2(128+33)
= 2 × 161
= 322 cm
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