The lateral surface area of a hollow cylinder is 4224sqcm. If it is cut along the height and forms a rectangular sheet of width 33cm. Find the perimeter of the sheet.
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Width of the rectangle = Circumference of cylinder
Height of cylinder=33cm
As the same cylinder is folded into a rectangular sheet the area will be the same
Area of rectangular sheet = 4224sqcm
length * width = 4224
l * 33 = 4224
length = 4224/33 = 128 cm
Therefore, perimeter = 2(l+b)
= 2(128 + 33)
= 2 *161
perimeter = 322cm
Height of cylinder=33cm
As the same cylinder is folded into a rectangular sheet the area will be the same
Area of rectangular sheet = 4224sqcm
length * width = 4224
l * 33 = 4224
length = 4224/33 = 128 cm
Therefore, perimeter = 2(l+b)
= 2(128 + 33)
= 2 *161
perimeter = 322cm
Answered by
1
Yes
Explanation
Refer the attachment.
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