Question

The lateral surface area of hollow cylinder 4224 cm². It cut Along its height and formed a rectangular sheet of width 33cm . Find the perimeter of rectangular sheet?​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Lateral surface area =2\pi rh=4224\ cm^22πrh=4224 cm

22\times\frac{22}{7}\times r\times h=4224\cm^22× 722×r×h=4224 cm2 rh=\frac{4224\times7}{22\times2} 22×2 4224×7rh=672 -1Width of rectangle=circumference of cylinder33=2\pi r33=2πr 33=2\times\frac{22}{7}\times r33=2× 72 ×r \frac{33\times7}{2\times22}=r

2×22

33×7 =r

r=5.25 cm

substituting r=5.25 cm - 1

5.25 h=672

h=128 cm

Now,for rectangular sheet,

l=128 cm b=33 cm

perimeter=2\left(l+b\right)2(l+b)

=2\left(128+33\right)2(128+33)

=2(161)

=322 cm