Question

The laundry basket is 10 m long 5 m and 3 m wide , What is the volume of laundry basket ?

Answer 1

Answer:

23 will be the volume of laundry basket

Answer 2

Step-by-step explanation:

Volume of cubes s

Volume of cubes s 3

Volume of cubes s 3 =8cm

Volume of cubes s 3 =8cm 3

Volume of cubes s 3 =8cm 3

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cm

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cm

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cmBreadth=Height=2 cm

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cmBreadth=Height=2 cmTotal surface area of the cuboid =2(lb+lh×+bh)

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cmBreadth=Height=2 cmTotal surface area of the cuboid =2(lb+lh×+bh)=>2[(4×2)+(4×2)+(2×2)] cm

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cmBreadth=Height=2 cmTotal surface area of the cuboid =2(lb+lh×+bh)=>2[(4×2)+(4×2)+(2×2)] cm 2

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cmBreadth=Height=2 cmTotal surface area of the cuboid =2(lb+lh×+bh)=>2[(4×2)+(4×2)+(2×2)] cm 2

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cmBreadth=Height=2 cmTotal surface area of the cuboid =2(lb+lh×+bh)=>2[(4×2)+(4×2)+(2×2)] cm 2 =>[2×(8+8+4)]cm

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cmBreadth=Height=2 cmTotal surface area of the cuboid =2(lb+lh×+bh)=>2[(4×2)+(4×2)+(2×2)] cm 2 =>[2×(8+8+4)]cm 2

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cmBreadth=Height=2 cmTotal surface area of the cuboid =2(lb+lh×+bh)=>2[(4×2)+(4×2)+(2×2)] cm 2 =>[2×(8+8+4)]cm 2

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cmBreadth=Height=2 cmTotal surface area of the cuboid =2(lb+lh×+bh)=>2[(4×2)+(4×2)+(2×2)] cm 2 =>[2×(8+8+4)]cm 2 =>[2×20]cm

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cmBreadth=Height=2 cmTotal surface area of the cuboid =2(lb+lh×+bh)=>2[(4×2)+(4×2)+(2×2)] cm 2 =>[2×(8+8+4)]cm 2 =>[2×20]cm 2

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cmBreadth=Height=2 cmTotal surface area of the cuboid =2(lb+lh×+bh)=>2[(4×2)+(4×2)+(2×2)] cm 2 =>[2×(8+8+4)]cm 2 =>[2×20]cm 2

Volume of cubes s 3 =8cm 3 Measure of each side s=2 cmThe two cubes are placed end to end.Then,Dimensions of the resulting cuboid =>Length=(2+2) cm=4 cmBreadth=Height=2 cmTotal surface area of the cuboid =2(lb+lh×+bh)=>2[(4×2)+(4×2)+(2×2)] cm 2 =>[2×(8+8+4)]cm 2 =>[2×20]cm 2 =>40cm