The law of conservation of energy is state that energy can neither be created nor be destroyed but it can only change one form in to another. Represent graphically, the variation of KE,PE and TE in the above case
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Answer:
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Answer:
consider a point A with some height H
at point A
PE = mgh and KE = half mv² = 0
so TE = mgh + 0 = mgh........(1)
now, at point B with height x , we have,
PE= mgh
= mg(h- x)
= mgh - mgx .........(a)
KE = ½mv²
using the 3rd equation of motion, we have
v² = u² +2 as
v²= 0² + 2gx ( u=0, a = g, s = x)
v²= 2gx
KE = ½ mv² = ½m ×2gx =mgx......(b)
TE = mgh-mgx +mgx
TE= mgh............(2)
now, at point c ,
PE =m× g×0 =0
KE =½ mv²
using 3rd equation of motion, we have ,
v² = u²+2as
v²=. 0²+2gh. ( u=0,a=g and s=h )
v² =2gh
KE =½ mv²
=½ m ×2gh
= mgh
now , TE = mgh +0= mgh.............(3)
so we should conclude that at different position the total energy remains same..
Explanation:
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