Question

the LCM and HCF of two number are 240 and 12 respectively. if one of the number is 48 then find the other number and arrange the following steps in sequential order.
A. 48 × x = 240 × 12 = x =
$\frac{240 \times 12}{48}$
B. product of two numbers = (their LCM)×(their HCF)
C. let the other number Be x
D. =x=5×12=60

Choose-
a. CABD
b. CBAD
c. BACD
d. CBDA​

Answer 1

Step-by-step explanation:

HCF×LCM= product of numbers

12×240=48×b

b=

48

12×240

b=60

Second number is 60