Question

The lcm and hcf of two numbers are 1472 and 41 of the numbers is 64 the other number is

Answer 1

$lcm \times hcf = first \: \: number \times second \: \: number \\ 1472 \times 41 = 64 \times second \: \: number \\ 1472 \times 41 \div 64 = second \: \: number \\ 943 = second \: number$

Answer 2

Answer:

The other number is 943

Step-by-step explanation:

Given that the LCM and HCF of two numbers which are 1472 and 41.

If one of the number is 64.

we have to find the other number.

Let the other number=x

LCM=1472

HCF=41

One number=64

The relation between LCM and HCF is

$LCM\times HCF=\text{Product of two numbers }$

$1472\times 41=64\times x$

$x=\frac{1472\times 41}{64}=943$

which is required number

Hence, the other number is 943