Question

The lcm and hcf of two numbers are 1760 and 32 respectively if one of the numbers is 160 find the other

Answer 1

Answer:

352 is the answer.

Step-by-step explanation:

lcm ×hcf ÷one number =the other number

1760×32 ÷160=352

Answer 2

Given:

The LCM and HCF of the two numbers are 1760 and 32 respectively and one of the numbers is 160.

To find:

The other number.

Solution:

First of all, we should know that the product of two numbers a and b is equal to the multiplication of their HCF and LCM.

This means,

$a \times b = HCF \times LCM$

Thus,

as given in the question, HCF = 32, LCM = 1760 and one number 'a' = 160,

the other number 'b' is given by:

$160 \times b = 1760 \times 32$

$b = \frac{1760 \times 32}{160}$

$b = 176 \times 2$

$b = 352$

Hence, the other number is 352.