Question

the LCM and HCF of two numbers are 180 and 6 respectively. if one of the number is 30 find the other.
​

Answer 1

Answer:

Given : LCM and HCF of two numbers are 180 and 6.

One number =30

Find : another number =?

Solution :

we know that two numbers product is equal their HCF and LCM product

Let another number =x

x×30=180×6

x=

30

180×6

x=36

Answer 2

Answer :-

• The other number is 36.

To find :-

• The other number.

Step-by-step explanation :-

 

• Here, it is given that the HCF and LCM of two numbers are 180 and 6 respectively and  one of the numbers is 30. We have to find the other number!

Let :-

• The other number be "x".

We know that :-

$\underline{\boxed{\sf{Product \: of \: two \: numbers = LCM \times HCF}}}$

Therefore,

$\mapsto \sf{30 \times x = 180 \times 6}$

$\mapsto \sf{30x = 180 \times 6}$

$\mapsto \sf{30x = 1080}$

$\mapsto \sf{x = \cancel{\dfrac{1080}{3}}}$

$\mapsto \sf{x = 36}$

Hence,

• The other number is 36.

_____________________________

Verification :-

• To check our answer, let's put 36 in the place of x and see whether LHS = RHS.

LHS

$\mapsto \rm{30 \times x}$  

$\mapsto \rm{30 \times x}$

$\mapsto \rm{30 \times 36}$

$\mapsto \rm{1080}$

RHS

$\mapsto \rm{180 \times 6}$

$\mapsto \rm{1080}$

LHS = RHS.

Hence verified!!

_____________________________