Question

the lcm And hcf of two numbers are 2310 and 33. if one of the number is 330, find the other number.

Answer 1

Lcm of two numbers(x,y) is 2310
HCF of x,y is 33
one number is 330.
let the no be x.
x=330
RULE: LCM x HCF = product of two numbers.

Therefore: x * y=lcm * hcf
330 * y= 2310 * 33
y= 2310 * 33/ 330
y=231

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Answer 2

Given :

HCF = 33

LCM = 2310

One of the two nos. = 330

Formula :

$\bf\purple{\fbox{Product\:of\:the\: numbers\:= HCF×LCM}}$

Assuming :

Other number = x

Solution :

Product of the numbers = HCF × LCM

=> 330 × x = 33×2310

=> x = 33×2310/330

=> x = 231

Answer :

• 231 is the other number.

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