Question

The LCM and HCF of two numbers are 240 and 12 respectively. If one of the numbers is 60, then find the other number.

Answer 1

LCM * HCF = one number *other number
= 240 * 12 = 60 * other number
= other number = 240*12 / 60
= other number = 4* 12
= other number = 48

Answer 2

$\bf{\underline{\underline \blue{Solution:-}}}$

$\sf\underline{\red{\:\:\: AnswEr:-\:\:\:}}$

• Th other required number = 48

$\sf\underline{\red{\:\:\: Given:-\:\:\:}}$

• The LCM and HCF of two numbers are 240 and 12 respectively.
• One of the numbers is 60.

$\sf\underline{\red{\:\:\: Need\:To\: Find:-\:\:\:}}$

• The other required number = ?

$\bf{\underline{\underline \blue{Explanation:-}}}$

Let other required number = y

$\sf\underline{\red{\:\:\: Formula\:Used\: Here:-\:\:\:}}$

$\bigstar \: \boxed{ \sf \: L.C.M \times H.C.F = Product \:of\: numbers }$

$\sf\underline{\green{\:\:\: Now,Putting\:the\: values:-\:\:\:}}$

$\dashrightarrow \sf {240 \times 12 = 60 \times y}$

$\dashrightarrow \sf {2880 = 60y}$

$\dashrightarrow \sf {y = \dfrac{\cancel{2280}}{\cancel{60}} }$

$\dashrightarrow \sf {y = \dfrac{\cancel{228}}{\cancel{6}} }$

$\dashrightarrow \sf {y = 48}$

$\sf\underline{\green{\:\:\: ThereFore:-\:\:\:}}$

• Th other required number is 48.

$\rule{200}{2}$