Question

the lcm and hcf of two numbers are 240 and 12 respectively if one of the number is 60 find the other number

Answer 1

lcm(a,b)×hcf(a,b)=a×b
therefore 240×12=a×60
=>a=48

Answer 2

we know,
HCF* LCM=product of two numbers
240 *12 =60*other number
other number=240*12/60
=48
hope it's helpful to you...