Question

the LCM and HCF of two numbers are 252 and 12 repectively . if one of the number is 36 find other

Answer 1

Answer:

84

Step-by-step explanation:

LCM = 252

HCF = 12

One Number = 36

Let the other no. be a.

We know that, LCM X HCF = Product of no.(s)

⇒ 252 x 12 = 36 x a

⇒ a = 252/3 = 84

Hope this helps.....

Answer 2

Answer:

Required other number is 84

Step-by-step explanation:

Here given,

LCM and HCF of two numbers are 252 and 12 repectively and one of the number is 36.

We want to find another number.

We know,

Product of two numbers = LCM × HCF

For example,

Let 2 and 3 be two numbers and their LCM is 6.

Therefore,

$2 \times 3 = 6 \times HCF \\ HCF = \frac{2 \times 3}{6} \\ = \frac{6}{6} \\ = 1$

Here given,

$LCM = 252 \\ HCF = 12$

and one number = 36

Let another number be x

According to rule,

$x \times 36 = 252 \times 12 \\ x = \frac{252 \times 12}{36} \\ x = \frac{252}{3} \\ x = 84$

Extra information:

HCF means Highest Common Factor

LCM means Largest Common Multiples

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