Question

the LCM and HCF of two numbers are 252 and 8 respectively. If one of the numbers is 42 , find the other number​

Answer 1

Answer:

1008

Step-by-step explanation:

LCM×HCF=a×b

252×8=42×b

b=252×8/2

b=1008

Answer 2

$\bf\purple{QuestioN:-}$

The LCM and HCF of two numbers are 252 and 8 respectively. If one of the numbers is 42 , find the other number​

$\bf\green{AnsweR:-}$

Gɩvɛɳ:-

LCM of two numbers = 252

HCF of two numbers = 8

One of the number = 42

To Fɩɲd:-

The other number = ??

Soɭʋtɩoɳ:-

The LCM of two numbers are given as 252

The HCF is given as 8.

As we know,

One of the number is 42.

Here we use the formula,

$\Large{\bf{\boxed{\bf{LCM[x,y]\times{HCF[x,y]=x\times{y}}}}}$

Let the unknown number be x.

According to this method,

$:\longrightarrow\bf{LCM\times{H}CF=42\times{x}}$

$:\longrightarrow\bf{252\times8=42x}$

$:\longrightarrow\bf{2,016=42x}$

$:\longrightarrow\bf{x=\dfrac{2016}{42}}$

$:\longrightarrow\bf{x=48}$

Then the unknown number is 48.

48 is the required answer for your question!

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