Question

The lcm and hcf of two numbers are 2970 and 30 respectively. Prime factors of the product of two numbers are:

a.2, 3, 5, 11

b.2, 3, 7, 11

c.2, 4, 5, 11

d.2, 3, 7, 13

Answer 1

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Solution is 2,3,5,11

Factors of [2970] = 2*3*5*3*3*11

Factors of [30] =     2*3*5HCF = 2*3*5 = 30

LCM = 2*3*5*32*11 = 30*99 = 2970

2970 = 2 * 5 * 3 * 3 * 11

30 = 2*3*5

LCM of the two numbers  = 2*3*3*3*5*11 = 2970

So the prime factors are = 2,3,5,11

The correct answer is option A