Question

the LCM and HCF of two numbers are 432 and 72 respectively if one of the number is 216 what is the other

Answer 1

Let LCM=432 and HCF =72

Let one number is “a”=216 and the other number is “b” which is unknown as b=?

To find b we as

LCM=a×b/HCF

LCM ×HCF /a=b putting the value we get

432×72/216=b

Therefor:

b=144

So the other number is 144.

Answer 2

Given,

The  LCM and HCF of two numbers are 432 and 72 respectively. One of the numbers is 216.

To Find,

What is the other number =?

Solution,

It is given to us that the LCM and HCF of two numbers are 432 and 72 respectively. One of the numbers is 216. We have to find the other number.

We know that the product of two given numbers is equal to the product of their HCF and LCM.

$Product\: of\: two\: numbers = Product\: of\: their\: HCF\: and\: LCM$

Let the other number be equal to x. Then,

$216*x = 432*72$

$216*x = 31104$

$x = \frac{31104}{216} = 144$

Hence, the other number is 144.