The lcm and hcf of two numbers are 560 and 40 respectively. If one number is 280 find the other number
Answers
Answered by
7
let no. to find be x.
We know that
LCM×HCF=No.1 × No.2
560×40=280× x
x =80
so required no. is 80
Hope it helps you.
ksgmani:
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LCM × HCF = 1st number × 2nd number
Yea thank you.... I know it but I want to check the procedure and answer
Anyways thanks a lot you helped me I had a doubt
okay.. no problem. Happy to help
Answered by
4
Product of two no. S = lcm× hcf
Let first no. Be x.
Thus,
128× x= 560× 40
x= 22400÷280
x = 80
Let first no. Be x.
Thus,
128× x= 560× 40
x= 22400÷280
x = 80
Dude it's 280 not 128
its. not 128 .. its 280
sry I had mistaken
Never mind
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