Question

The LCM and HCF of two numbers is 132 and 12 repectively . If one of the number is 12 then find the other number.​

Answer 1

Answer:

Given, HCF=12, LCM=72

One number =x, Other number =60−x

∴ Product of the two numbers = HCF × LCM

⇒x(60−x)=12×72

⇒x

2

−60x+864=0

⇒x

2

−36x−24x+864=0

⇒x(x−36)−24(x−36)=0

⇒(x−36)(x−24)=0

⇒x=36 or 24

∴ One of the number is 24.

Answer 2

Step-by-step explanation:

refer to the given attachment Hope it helps you