The LCM and HCF of two numbers is 132 and 12 repectively . If one of the number is 12 then find the other number.
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Answer:
Given, HCF=12, LCM=72
One number =x, Other number =60−x
∴ Product of the two numbers = HCF × LCM
⇒x(60−x)=12×72
⇒x
2
−60x+864=0
⇒x
2
−36x−24x+864=0
⇒x(x−36)−24(x−36)=0
⇒(x−36)(x−24)=0
⇒x=36 or 24
∴ One of the number is 24.
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Step-by-step explanation:
refer to the given attachment Hope it helps you
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