Question

the LCM and HCF of two
numbers is 341 and 11 respectively
find the greater of two numbers? *​

Answer 1

Given that:

• LCM of two numbers = 341
• HCF of two numbers = 11

To Find:

• The greater of two numbers.

Let us assume:

• The greater number be x.
• And the smaller number be y.

LCM and HCF of x and y:

By prime factorisation method.

• Factors of x = x
• Factors of y = y

LCM (x, y) = 341 = 11 × 31

HCF (x, y) = 11

If and only if,

• Factors of x = 11 × 31
• Factors of y = 11

Then, LCM and HCF of x and y will be 341 and 11 respectively.

So,

• Greater number = 11 × 31 = 341

Hence,

• The greater of two numbers is 341.

Answer 2

Given :-

LCM = 341

HCF = 11

To Find :-

Numbers

Solution :-

HCF(a,b) = 11

Let the numbers be a and b

Now, Let x and y be the being relatively prime number

So,

a = 11x

b = 11y

Given, LCM is 341

(11m,11n) = 341

Taking 11 as common

11(mn) = 341

mn = 341/11

mn = 31

Now

The only two integer could be 11 and 341

Hence

Greater number is 341